A proton and a deuteron, accelerated through same potential difference enters in a region of uniform magnetic field with their velocities perpendicular to the magnetic field. The ratio of proton to the deuteron is

1 : 1

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1 : \sqrt{2}

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1 : 2

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1 : 4

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Solution

The correct option is B $1 : 1$
$Solution$ :
As we know that the energy gained by charged particle of charge q when accelerated under a potential difference VV will be
E $_{k}$ =qV
$∴$ for a given V,
E $_{k} \propto q$
Therefore for proton and deuteron, the ratio of charges is 1 : 1

$Hence A is the correct option$

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A proton and a deuteron, accelerated through same potential difference enters in a region of uniform magnetic field with their velocities perpendicular to the magnetic field. The ratio of proton to the deuteron is

The correct option is B 1:1Solution:As we know that the energy gained by charged particle of charge q when accelerated under a potential difference VV will beEk=qV∴ for a given V, Ek∝qTherefore for proton and deuteron, the ratio of charges is 1 : 1Hence A is the correct option

Solution:

As we know that the energy gained by charged particle of charge q when accelerated under a potential difference VV will be

Ek=qV

∴ for a given V,

Ek∝q

Therefore for proton and deuteron, the ratio of charges is 1 : 1

Hence A is the correct option

$Solution$ :

E $_{k}$ =qV

$∴$ for a given V,

E $_{k} \propto q$

$Hence A is the correct option$