A proton and a deuteron are sent into an electric field. The ratio between the accelerations of proton and deuteron is:

2 : 1

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1 : 2

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1 : 1

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4 : 1

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Solution

The correct option is A $2 : 1$
Deutron has same charge as proton but mass of deutron is twice that of proton.
So, $m_{d} = 2 m_{p}; q_{d} = q_{p}$
We know that force, $F = E q$
So, $F_{d} = E q_{d}; F_{p} = E q_{p}$
And acceleration, $a = \frac{F}{m}$
So, $a_{d} = \frac{E q_{d}}{m_{d}}; a_{p} = \frac{E q_{p}}{m_{p}}$
$\Rightarrow$ $a_{p} : a_{d} = \frac{E q_{p}}{m_{p}} : \frac{E q_{d}}{2 m_{p}}$
$\Rightarrow$ $a_{p} : a_{d} = 2 : 1$

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A proton and a deuteron are sent into an electric field. The ratio between the accelerations of proton and deuteron is:

The correct option is A 2:1Deutron has same charge as proton but mass of deutron is twice that of proton.So, md=2mp;qd=qpWe know that force, F=EqSo, Fd=Eqd;Fp=EqpAnd acceleration, a=FmSo, ad=Eqdmd;ap=Eqpmp⇒ ap:ad=Eqpmp:Eqd2mp⇒ ap:ad=2:1