A proton and an electron are placed in a uniform electric field.
(a) The electric forces acting on them will be equal.
(b) The magnitudes of the forces will be equal.
(c) Their accelerations will be equal.
(d) The magnitudes of their accelerations will be equal.

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Solution

(b) The magnitudes of the forces will be equal.

We know:
$\vec{F} = q \vec{E}$

For an electron and a proton, the value of q will be same, but the sign will be opposite.
Hence, they will experience a force that will be equal in magnitude but opposite in direction.
Now,
$\vec{F} = q \vec{E} = m \vec{a} \Rightarrow \vec{a} = \frac{q \vec{E}}{m}$

As the electron and proton have different values of mass m, they will have different magnitudes of acceleration. Also, they will differ in direction due to the opposite signs of q.

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A proton and an electron are placed in a uniform electric field. (a) The electric forces acting on them will be equal. (b) The magnitudes of the forces will be equal. (c) Their accelerations will be equal. (d) The magnitudes of their accelerations will be equal.

A proton and an electron are placed in a uniform electric field.
(a) The electric forces acting on them will be equal.
(b) The magnitudes of the forces will be equal.
(c) Their accelerations will be equal.
(d) The magnitudes of their accelerations will be equal.