A proton beam enters a magnetic field of 10−4Wbm−2 normally. If the specific charge of the proton is 1011Ckg−1 and its velocity is 109ms−1, then the radius of the circle described will be
A
0.1m
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B
10m
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C
100m
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D
1m
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Solution
The correct option is C100m Given : B=10−4Wb/m2q=1011C/kgv=109m/s