A proton describes a circle of radius 1 cm in a magnetic field of strength 0.10 T. What would be the radius of the circle described by an $α -$ particle moving with the same speed in the same magnetic field ?

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Solution

$r_{1} = \frac{m v}{q B}, r_{2} = \frac{2 m V}{q B}$

$\frac{r_{1}}{r_{2}} = 2 ∴ r_{2} = 2 c m$

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A proton describes a circle of radius 1 cm in a magnetic field of strength 0.10 T. What would be the radius of the circle described by an α−particle moving with the same speed in the same magnetic field ?

r1=mvqB, r2=2m VqB r1r2=2 ∴ r2=2 cm

A proton describes a circle of radius 1 cm in a magnetic field of strength 0.10 T. What would be the radius of the circle described by an $α -$ particle moving with the same speed in the same magnetic field ?

$r_{1} = \frac{m v}{q B}, r_{2} = \frac{2 m V}{q B}$

$\frac{r_{1}}{r_{2}} = 2 ∴ r_{2} = 2 c m$