A proton enters a magnetic field with a velocity of 1-5 - 105 m - s making an angle of 30- with the field- What is the force experienced by the proton if B - 3-0 T-A- 3-6 - 10-14 NB- 2-4 - 10-14 NC- 4-8 - 10-14 ND- 1-2 - 10-14 N

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The Circular Motion

A proton ente...

Question

A proton enters a magnetic field with a velocity of 1.5 x 10⁵m/s making an angle of 30^owith the field. What is the force experienced by the proton if B = 3.0 T.

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Solution

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Similar questions

2.5 \times 10^{7} m s^{- 1}

30^{0}

(B = 25 T)

1.5 w e b e r / m^{2}

2 \times 10^{7} m / s e c

30^{o}

0.3 T

4 \times 10^{5} m / s

60^{\circ}

e = 1.6 \times 10^{- 19} C

m = 1.67 \times 10^{- 27} k g

1.5 W b / m^{2}

2 \times 10^{7}

30^{o}

4.0 \times 10^{5} m s^{- 1}

60^{o}

1.2 \times 10^{- X} m

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