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Byju's Answer
Standard XII
Physics
Braking Radiation
A proton is a...
Question
A proton is accelerated through a potential of 1V then its energy will be ?
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Solution
Potential difference (V) = 1 V,
K.E. acquired = q V
= 1.6 × 10
-19
x 1
= 1.6 × 10
-19
joules
= 1 eV
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