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Helical Motion

A proton is m...

Question

A proton is moving with a velocity of $3 \times 10^{7} m / s$ in the direction of a uniform magnetic field of $0.5 T$ . The force acting on proton is

2 N

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4 N

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6 N

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zero

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Solution

The correct option is B zero
${\to F}_{m a g n e t i c} = q (\to v \times \to B)$
Since $\to v ∥ \to B$
${\to F}_{m a g n e t i c} = 0$

Suggest Corrections

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