A proton is projected with a speed of 3-106m-s horizontally from east to west- A uniform magnetic field B of strength 2-10-3T exists in the vertically upward direction the magnitude of magnetic force on proton is F-10-16N- What is the value of F-

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Standard XII

Physics

Capacitance of Parallel Plate Capacitor

A proton is p...

Question

A proton is projected with a speed of $3 \times 10^{6} m / s$ horizontally from east to west. A uniform magnetic field B of strength $2 \times 10^{- 3} T$ exists in the vertically upward direction the magnitude of magnetic force on proton is $F \times 10^{- 16} N$ . What is the value of $F$ ?

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Solution

Magnetic force is given as $F = q v B s i n θ$ it is given that angle between field $B$ and velocity $v$ is $90^{0}$ and $q = 1.6 \times 10^{- 19} C$ so we get the value of force by just putting the values as they are because all are in SI system as $F o r c e = 6 \times 1.6 \times 10^{- 16} N$ so $F = 6$ is the required answer.

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A proton is projected with a speed of 3×106m/s horizontally from east to west. A uniform magnetic field B of strength 2×10−3T exists in the vertically upward direction the magnitude of magnetic force on proton is F×10−16N. What is the value of F?

Magnetic force is given as F=qvBsinθ it is given that angle between field B and velocity v is 900 and q=1.6×10−19C so we get the value of force by just putting the values as they are because all are in SI system as Force=6×1.6×10−16N so F=6 is the required answer.

A proton is projected with a speed of $3 \times 10^{6} m / s$ horizontally from east to west. A uniform magnetic field B of strength $2 \times 10^{- 3} T$ exists in the vertically upward direction the magnitude of magnetic force on proton is $F \times 10^{- 16} N$ . What is the value of $F$ ?