Given:
Velocity of the proton, v = 3 × 106 m s−1
Uniform magnetic field, B = 0.6 T
As per the question, the proton is projected perpendicular to a uniform magnetic field.
We know,
F = mpa ....(i)
and
F = evBsinθ ....(ii)
On equating (i) and (ii), we get:
ma = evBsinθ (As θ = 90˚)
= 1.72 × 1014 m/s2