A proton is traveling due north. If a uniform magnetic field is applied vertically down then the particle
a) deflected towards west
b) revolves in anti clock wise direction
c) acquires acceleration
d) comes to rest

a, b, c are correct

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a, d are wrong

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b, d are wrong

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b, c, d are correct

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Solution

The correct option is A a, b, c are correct
$\to F = q (\to V \times \to B)$
So, $\to V \times \to B$ direction will be in west by right hand thumb rule. So, it will revolves in anti-clockwise direction and it acquires radial acceleration.

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A proton is traveling due north. If a uniform magnetic field is applied vertically down then the particlea) deflected towards westb) revolves in anti clock wise directionc) acquires acceleration d) comes to rest

The correct option is A a, b, c are correct→F=q(→V×→B)So, →V×→B direction will be in west by right hand thumb rule. So, it will revolves in anti-clockwise direction and it acquires radial acceleration.

A proton is traveling due north. If a uniform magnetic field is applied vertically down then the particle
a) deflected towards west
b) revolves in anti clock wise direction
c) acquires acceleration
d) comes to rest

The correct option is A a, b, c are correct
$\to F = q (\to V \times \to B)$
So, $\to V \times \to B$ direction will be in west by right hand thumb rule. So, it will revolves in anti-clockwise direction and it acquires radial acceleration.