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Question

A proton moves at a constant velocity of 50 m/s along the x-axis, in uniform electric and magnetic fields.The magnetic field is B=(2.0mT)^j.What is the electric field?

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Solution

Since the proton moves with constant velocity, the net force acting on it is zero.
Hence the electric field and magnetic force cancel each other.
qE=q(v×B)
E=(0.1V/m)^k

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