You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Analysis of Force Equation

A proton movi...

Question

A proton moving with a velocity V is acted upon by electric field E and magnetic field B. The proton will move undeflected if

E is perpendicular to B

No worries! We‘ve got your back. Try BYJU‘S free classes today!

E is parallel to V and perpendicular to B

No worries! We‘ve got your back. Try BYJU‘S free classes today!

E is parallel to B and both are perpendicular to V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

E, V and B are mutually perpendicular and

V = E / B

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is B E, V and B are mutually perpendicular and $V = E / B$
Force due to magnetic field $=$ Force due to electric field
$q (\to V \times \to B) = q \to E$
$\Rightarrow \to V \times \to B = \to E$
So, E, V and B are mutually perpendicular and VB = E $(∵ s i n 90^{0} = 1)$
or $V = \frac{E}{B}$

Suggest Corrections

Similar questions

Q. A proton moving with velocity

V

is acted upon by electric field

E

and magnetic field

B

. The proton will move undeflected if

Q. A charged particle goes undeflected in a region containing electric and magnetic fields. It is possible that

(i) \to E | | \to B, \to V | | \to E

(i i) \to E

is perpendicular to

\to B

and both are perpendicular to

\to V

(i i i) \to V | | \to B

, but

\to E

is not parallel to

\to B

(i v) \to E | | \to B

, but

\to V

is not parallel to

\to E

Q. A charged particle goes undeflected in a region of space containing an electric field

\to E

and a magnetic field of intensity

\to B

. Which of the following is possible?

Q. If a charged particle moves unaccelerated in a region containing electric and magnetic fields,
(a)

\vec{E}

must be perpendicular to

\vec{B}

(b)

\vec{v}

must be perpendicular to

\vec{E}

(c)

\vec{v}

must be perpendicular to

\vec{B}

(d) E must be equal to vB

Q. In J.J. Thomson’s method, electric field

E

, magnetic field

B

and velocity

v

of the electron were in mutually perpendicular direction. This velocity selector allows particles of velocity

v

to pass undeflected when
(correct answer + 1, wrong answer - 0.25)

Join BYJU'S Learning Program

A proton moving with a velocity V is acted upon by electric field E and magnetic field B. The proton will move undeflected if

The correct option is B E, V and B are mutually perpendicular and V=E/BForce due to magnetic field =Force due to electric fieldq(→V×→B)=q→E⇒→V×→B=→ESo, E, V and B are mutually perpendicular and VB = E (∵sin900=1)or V=EB