Question

a pulley is attached to the celing of a lift moving upwards. Two particles are attached to the two ends of a string passing over the pulley, the masses of the particles are in the ratio 2:1. If the acceleration of the particles relative to the lift is $g/2$, then the acceleration of the lift will be

• A. $g$
• B. $\frac{g}{2}$
• C. $\frac{g}{3}$
• D. $\frac{g}{4}$

Answer 1

The correct option is B $\frac{g}{2}$

Now, for mass$=2m$

So, $2mg+2ma-T=2m{a}^{\prime }$

Given, $a^{\prime }=\frac{g}{2}$

So putting the value of $a^{\prime }$

$a=\frac{g}{2}$ (acceleration of lift)