A pulley system has a velocity ratio of 4 and an efficiency of 90%. Calculate, the effort required to raise a load of 300 N by the system is

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Solution

$M . A . = \frac{L o a d}{E f f o r t}$
$\Rightarrow L o a d = M . A . \times E f f o r t$
$= 3.6 \times 300 = 1080 N$

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