A pulley system of VR of 2 and efficiency of 50%. If the effort moves through a distance of 5m. Calculate the distance moved by the load.

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5.6m

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10m

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2.5m

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Solution

The correct option is D 2.5m
Given: $V R = 2$
From the relation $V R = \frac{Distance moved by effort}{distance moved by load}$
Using formula we get distance moved by the load is $2.5 m$

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A pulley system of VR of 2 and efficiency of 50%. If the effort moves through a distance of 5m. Calculate the distance moved by the load.

The correct option is D 2.5mGiven: VR=2From the relation VR=Distance moved by effortdistance moved by loadUsing formula we get distance moved by the load is 2.5m

The correct option is D 2.5m
Given: $V R = 2$
From the relation $V R = \frac{Distance moved by effort}{distance moved by load}$
Using formula we get distance moved by the load is $2.5 m$