A pulley system with a velocity ratio of 4 is used to lift a load of 100kgf through a vertical height is 15m. The effort required to do so is 40kgf which is applied in the downward direction. calculate the mechanical advantage of a pulley.

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Solution

Given
Load = 100kgf
Effort = 40 kgf
Formula
$M e c h a n i c a l A d v a n t a g e = \frac{L o a d}{E f f o r t} = \frac{100}{40} = 2.5$

Hence the mechanical advantage is 2.5

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A pulley system with a velocity ratio of 4 is used to lift a load of 100kgf through a vertical height is 15m. The effort required to do so is 40kgf which is applied in the downward direction. calculate the Distance through which effort is applied?

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A pulley system with a velocity ratio of 4 is used to lift a load of 100kgf through a vertical height is 15m. The effort required to do so is 40kgf which is applied in the downward direction. calculate the mechanical advantage of a pulley.

GivenLoad = 100kgfEffort = 40 kgfFormulaMechanicalAdvantage=LoadEffort=10040=2.5 Hence the mechanical advantage is 2.5

Given
Load = 100kgf
Effort = 40 kgf
Formula
$M e c h a n i c a l A d v a n t a g e = \frac{L o a d}{E f f o r t} = \frac{100}{40} = 2.5$

Hence the mechanical advantage is 2.5