A pump can fill a tank in 3 hrs. Due to a leakage, it took $3 \frac{1}{2}$ hrs to fill it up completely. If the tank is full, how long will it take for the leakage to empty it?

21 hrs

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20 hrs

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30 hrs

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40 hrs

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50 hrs

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Solution

The correct option is A
21 hrs

Work done by the leakage in 1 hr = $(\frac{1}{3}) - (\frac{2}{7}) = \frac{1}{21}$

So the leakage will empty the tank in 21 hrs.

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Similar questions

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A pump can fill a tank in 3 hrs. Due to a leakage, it took 312 hrs to fill it up completely. If the tank is full, how long will it take for the leakage to empty it?

The correct option is A 21 hrs Work done by the leakage in 1 hr = (13)−(27)=121 So the leakage will empty the tank in 21 hrs.

A pump can fill a tank in 3 hrs. Due to a leakage, it took $3 \frac{1}{2}$ hrs to fill it up completely. If the tank is full, how long will it take for the leakage to empty it?

The correct option is A
21 hrs

Work done by the leakage in 1 hr = $(\frac{1}{3}) - (\frac{2}{7}) = \frac{1}{21}$

So the leakage will empty the tank in 21 hrs.