A pump can lift water of $150 k g$ in $25 s$ to store it in an overhead tank. The tank is located at a height of $15 m$ . Find the power of the pump. $(T a k e g = 9.8 m s^{- 2})$

700 W

No worries! We‘ve got your back. Try BYJU‘S free classes today!

800 W

No worries! We‘ve got your back. Try BYJU‘S free classes today!

900 W

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1000 W

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $900 W$
Given,
Mass of water = $150 k g$
Time taken by pump = $25 s$
Height = $15 m$
Hence, work done by the pump $= m \times g \times h = (150 \times 9.8 \times 15$ J = $22500 J$

$P o w e r = \frac{W o r k d o n e}{t i m e t a k e n} = (\frac{22500}{25}) = 900 W$

Suggest Corrections

Similar questions

A pump can lift water of 150 kg in 15 s, to store it in an overhead tank at a height of 15 m. Find the power of the pump. $(g = 9.8 m s^{- 2})$

m / s^{2}

What is the power of a pump which takes 10 seconds to lift 100 kg of water to a water tank situated at a height of 20 m? Take $g = 10 m s^{- 2}$

30 m^{3}

15 m i n

40 m

30 %

10^{3} k g m^{- 3}

(g = 9.8 m s^{- 2})

Join BYJU'S Learning Program