A pure breeding plant with red dot on leaves was crossed with pure breeding white dotted plants. The heterozygotes have both red and white dots. On self pollination of $F_{1}$ , what fraction of plants show both red and white dot on leaves ________________.

\frac{1}{2}

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\frac{1}{4}

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\frac{2}{3}

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\frac{3}{4}

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Solution

The correct option is A $\frac{1}{2}$

A pure breeding plant with red dots on leaves was crossed with pure breeding white dotted plants. F1 plants shows both red and white dots on leaves. On self pollination of F1, in the F2 generation, 1 plant with red dot leaves, 2 plants with Red & white dot leaves, 1 plant with white dot leaves. It is called codominance.
So, the correct option is ‘1/2’.

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A pure breeding plant with red dot on leaves was crossed with pure breeding white dotted plants. The heterozygotes have both red and white dots. On self pollination of F1, what fraction of plants show both red and white dot on leaves ________________.

A pure breeding plant with red dot on leaves was crossed with pure breeding white dotted plants. The heterozygotes have both red and white dots. On self pollination of $F_{1}$ , what fraction of plants show both red and white dot on leaves ________________.