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Question

a pure colourless liquid (X) having B.P 118 celsius which is hygroscopic and miscible with water.X on heating with P2O3 loses water form compound Y. X and Y respectively are?​

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Solution

The compound is definitely an alcohol and the boiling point of the compound matches with butanol. Butanol is less hygroscopic and is miscible with water. Butanol on heating with P2O5 loses water molecule forming butene (alkene)
So the compound X is butanol
Y is butene
CH3CH2CH2CH2OH - H2OP2O5 CH3CH2CH=CH2Butanol Butene

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