Question

A pure substance at $8MPa$ and ${400}^{o}C$ is having a specific internal energy of $2864kJ/kg$ and a specific volume of $0.03432m^3/kg$. Its specific enthalpy (in $kJ/kg$) is

• A. 3138.56

Answer 1

The correct option is A 3138.56
$p=8MPa=8\times {10}^{3}kPa$

$T={400}^{o}C$

$u=2864kJ/kg$

$v=0.03432m^3/kg$

By definition of specific enthalpy,

$h=u+pv=2864+8\times {10}^3\times 0.03432$

$=3138.56kJ/kg$