A push back toy car of mass 20g pushed backwards with a force of 40 dynes for 5 seconds due west. Find the distance travelled by the car backwards.

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Solution

$f = 40 d y n e s = 40 \times 10^{- 5} N m = 20 g a c c e l e r a t i o n o f t h e b o d y = a = \frac{40 \times 10^{- 5}}{20} = 2 \times 10^{- 5} m / s^{2} d i s \tan c e t r a v e l l e d i n 5 s e c o n d s : s = u t + \frac{1}{2} a t^{2} s = 0 + 0.5 \times 2 \times 10^{- 5} \times 25 = 25 \times 10^{- 5} m = 250 m i c r o m e t e r$

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A push back toy car of mass 20g pushed backwards with a force of 40 dynes for 5 seconds due west. Find the distance travelled by the car backwards.

f= 40 dynes = 40×10-5 Nm = 20 gacceleration of the body = a =40×10-520 = 2×10-5 m/s2distance travelled in 5 seconds:s = ut +12at2s = 0 + 0.5×2×10-5×25 = 25×10-5 m = 250 micro meter