A quadratic equation $a x^{2} + b x + c = 0$ has no real roots if:

b^{2} - 4 a c = 0

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b^{2} > 4 a c

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b^{2} < 4 a c

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b^{2} + 4 a c = 0

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Solution

The correct option is C $b^{2} < 4 a c$
For no real roots
$b^{2} - 4 a c$
$b^{2} < 4 a c$

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Similar questions

The roots of a quadratic equation $a x^{2} + b x + c = 0$ are given by $\frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$ , provided $b^{2} - 4 a c \geq 0$ .

Q. What is the nature of the roots of the quadratic equation

a x^{2} + b x + c = 0

if
(a)

b^{2} - 4 a c = 0

(b)

b^{2} - 4 a c < 0

Q. For the equation

a x^{2} + b x + c = 0

which of the following statements is incorrect?
(a) If (b² − 4ac) < 0, the roots are imaginary.
(b) If (b² − 4ac) = 0, the roots are real and equal.
(c) If (b² − 4ac) > 0 and (b² − 4ac) is a perfect square, then the roots are rational and unequal.
(d) (b² − 4ac) < 0, the roots are irrational.

Q. What are the roots of the quadratic equation

a x^{2} + b x + c = 0 ?

If b² – 4ac = 0 then The roots of the Quadratic equation ax² + bx + c = 0 are given by :

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A quadratic equation ax2+bx+c=0 has no real roots if:

The correct option is C b2<4acFor no real rootsb2−4acb2<4ac

A quadratic equation $a x^{2} + b x + c = 0$ has no real roots if:

The correct option is C $b^{2} < 4 a c$
For no real roots
$b^{2} - 4 a c$
$b^{2} < 4 a c$