A quadratic equation whose one root is 3 is

x^{2} - 6 x - 5 = 0

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x^{2} + 6 x - 5 = 0

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x^{2} - 5 x - 6 = 0

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x^{2} - 5 x + 6 = 0

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Solution

The correct option is C $x^{2} - 5 x + 6 = 0$
For option A :
$x^{2} - 6 x - 5 = 0$ - - - - - can not be factorized and thus we see option B & C also can not be factorized.
Now, option D
$x^{2} - 5 x + 6 = 0 \Rightarrow x^{2} - 3 x - 2 x + 6 - 0 \Rightarrow x (x - 3) - 2 (X - 3) = 0 \Rightarrow (x - 3) (x - 2) = 0 \Rightarrow x = 3 or x = 2$
Hence, option D is correct.

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