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Question

A quadratic polynomial p(x) has 1+5 and 15 as its zeros and p(1)=2. Then the value of p(0) is

A
45
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B
85
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C
85
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D
45
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Solution

The correct option is B 85
Let
p(x)=a(x(1+5))(x(15))
p(x)=a(x2x(1+5+15)+(15))p(x)=a(x22x4)
Now,
p(1)=2
2=a(124)a=25
p(x)=25(x22x4)p(0)=85

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