A quadratic polynomial whose zeros are 5 and −3, is
(a) x2+2x−15
(b) x2−2x+15
(c) x2−2x−15
(d) none of these
The correct option is (c): x2−2x−15
Here, the zeroes are 5 and −3.
Let α=5 and β=−3 [α and β are the zeros of the polynomial]
So, sum of the zeroes, α+β=5+(−3)=2
Also, the product of the zeroes, αβ=5×(−3)=−15
The polynomial will be x2−(α+β)x+αβ.
∴ The required polynomial is x2−2x−15.