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Question

A quadrilateral ABCD is drawn in which the mid points of sides AB, BC, CD and AD are P, Q, R and S respectively.

If quadrilateral ABCD is a rectangle, what can be said about quadrilateral PQRS?


A

Rhombus

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B

Parallelogram

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C

Square

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D

Can’t say

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Solution

The correct option is A

Rhombus



As ABCD is a rectangle, the diagonals AC and BD bisect each other and are equal in length.

By mid point theorem,

PS = QR = 12BD --------------------------- I

PQ = RS = 12AC ---------------------------- II

But, BD = AC

Therefore, PQ = QR = RS = PS => sides are equal.

So, PQRS is either a rhombus or a square.

Also, AOB ≅ SRQ By SSS criteria

Thus, ∠AOB = ∠SRQ (by CPCTE)

We know that, diagonals of a rectangle do not intersect at 90°.

Therefore, ∠SRQ ≠ 90°

Hence, PQRS is a rhombus.


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