CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

A quantity of $$1\ g$$ of metallic carbonate $$XCO_3$$ is completely converted into a chloride. $$XCl_2$$ weighing $$1.11\ g$$. The atomic mass of the element '$$X$$' is ____________.


A
10
loader
B
20
loader
C
30
loader
D
40
loader

Solution

The correct option is D $$40$$
$$XCO_3 \longrightarrow XCl_2$$
$$1\ gm\quad \quad 1.11\ gm$$
$$\frac { mole\ of\ { XCO }_{ 3 }\\ \downarrow \\ 1 }{ M+12+48 } \begin{matrix} \longrightarrow  \\ = \end{matrix}\frac { mole\ of\ { XCl }_{ 2 }\\ \downarrow \\ 1.11 }{ M+71 }$$

where, $$M=$$ molar mass of $$X$$.

Now,
$$M+71=(M+60)1.11$$
$$M+71=1.11\ M+66.6$$
$$4.4=0.11\ M$$
$$M=40$$
Option $$(D).$$

Physics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image