A quantity of air is taken from state a to state b along a path that is a straight line in the P-V diagram.In this process, what happens to the temperature of the gas?
A quantity of air is taken from state a to state b along a path that is a straight line in the P-V diagram.In this process, what happens to the temperature of the gas?
The correct option is B Increases
The process shown in the graph is where P is linearly proportional to V. So pressure can be expressed as -
p=m×V+c- - - - - (1)
where m and c are constants.
We know that all ideal gases behave in a manner where if their pressures tend to zero their volume also tends to zero. So the value of c = 0 (since the straight line representing P as a function of V passes through the origin).
Now using ideal gas equation -
PV = nRT.- - - - - (2)
We get, mV2=nRT.- - - - - (3)
As the volume increases in the process as we move from a → b, equation (3) suggests that the temperature will also increase.
Increases
The process shown in the graph is where P is linearly proportional to V. So pressure can be expressed as -
p=m×V+c- - - - - (1)
where m and c are constants.
We know that all ideal gases behave in a manner where if their pressures tend to zero their volume also tends to zero. So the value of c = 0 (since the straight line representing P as a function of V passes through the origin).
Now using ideal gas equation -
PV = nRT.- - - - - (2)
We get, mV2=nRT.- - - - - (3)
As the volume increases in the process as we move from a → b, equation (3) suggests that the temperature will also increase.
