A quantity of electricity required to reduce 12.3 g of nitrobenzene to aniline arising $50 %$ current efficiency is:

1158000C

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579000C

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231600C

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289500C

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Solution

The correct option is
A
115800C
Equivalent mass of nitrobenzene $= \frac{M o l e c u l a r m a s s}{6}$
$= \frac{123}{6} = 20.5$
We know that formula $w = \frac{E \times i \times t}{96500}$
Since,current efficiency is 50% $i = \frac{50 i_{0}}{100}$
= $\frac{20.5 \times i_{o} \times t \times 50}{96500 \times 100} = i_{o} \times t = 115800 c$
$∴$ The quantity of electricity required is 115800c

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A quantity of electricity required to reduce 12.3 g of nitrobenzene to aniline arising 50% current efficiency is:

The correct option is A 115800CEquivalent mass of nitrobenzene =Molecular mass6 =1236=20.5We know that formula w=E×i×t96500 Since,current efficiency is 50% i=50i0100 = 20.5×io×t×5096500×100=io×t=115800c ∴ The quantity of electricity required is 115800c

A quantity of electricity required to reduce 12.3 g of nitrobenzene to aniline arising $50 %$ current efficiency is: