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Byju's Answer
Standard X
Chemistry
Ionisation Energy
A quantity of...
Question
A quantity of
P
C
l
5
was heated in 10
d
m
3
vessel
250
o
C
P
C
l
5
(g) ⇌
P
C
l
3
(g) +
C
l
2
(g)
At equilibrium the vessel contains 0.1 mole of
P
C
l
5
and 0.2 mole of
C
l
2
The equilibrium constant of the reaction is:
A
0.05
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B
0.02
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C
0.025
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D
0.04
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Solution
The correct option is
D
0.04
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Similar questions
Q.
A quantity of
P
C
l
5
was heated in
10
d
m
3
vessel
250
0
C
P
C
l
5
g) ⇌
P
C
l
3
(g) +
C
l
2
(g)
At equilibrium the vessel contains 0.1 mole of
P
C
l
5
and 0.2 mole of
C
l
2
. The equilibrium constant of the reaction is ?
Q.
A quantity of
P
C
l
5
was heated in a 10 litre vessel as
250
o
C
;
P
C
l
5
(
g
)
⇌
P
C
l
3
(
g
)
+
C
l
2
(
g
)
. At equilibrium the vessel contains 0.1 mole of
P
C
l
5
. 0.20 mole of
P
C
l
3
and 0.2 mole of
C
l
2
. The equilibrium constant of the reaction is:
Q.
A quantity of
P
C
l
5
was heated in a 10 litre vessel at
250
∘
C
P
C
l
5
(
g
)
⇌
P
C
l
3
(
g
)
+
C
l
2
(
g
)
.
At equilibrium, the vessel contains 0.1 mole of
P
C
l
5
, 0.2 mole of
P
C
l
3
and 0.2 mole of
C
l
2
. The equilibrium constant is :
Q.
A quantity of
P
C
l
5
was heated in a
10
litre vessel at
250
o
C
P
C
l
5
(
g
)
⇌
P
C
l
3
(
g
)
+
C
l
2
(
g
)
At equilibrium the vessel contains
0.25
moles of
P
C
l
5
,
0.3
mole of
P
C
l
3
,
0.30
moles of
C
l
2
(a) Compute the equilibrium constant for the formation of
P
C
l
5
at
250
o
C
(b) What is
Δ
G
o
for the dissociation of
P
C
l
5
? [
log
0.036
=
−
1.443
]
Q.
Two moles of
P
C
l
5
were heated in closed vessel of 2 litre capacity. At equilibrium, 40% of
P
C
l
5
was dissociated into
P
C
l
3
and
C
l
2
.
The value of the equilibrium constant is :
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