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Question

A quantity of PCl5 was heated in a 10 litre vessel as 250oC;PCl5(g)PCl3(g)+Cl2(g). At equilibrium the vessel contains 0.1 mole of PCl5. 0.20 mole of PCl3 and 0.2 mole of Cl2. The equilibrium constant of the reaction is:

A
0.02
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B
0.05
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C
0.04
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D
0.025
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Solution

The correct option is A 0.04
PCl5(g)PCl3(g)+Cl2(g)
0.1 0.2 0.2
given, Volume of vessel =10 litres
K=[PCl3][Cl2][PCl5]
=(0.20/10)(0.20/10)(0.1/10)=0.04
equilibrium constant of this reaction is order.

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