A quarter cylinder of radius R and refractive index 1.5 is placed on a table. A point object P is kept at a distance of mR from it. The value of ′m′ for which a ray from P will emerge parallel to the table, as shown in figure, is
A
4/3
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B
3/4
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C
3/2
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D
2/3
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Solution
The correct option is A4/3 Applying the lens formula for the plane surface,
1.5v1−1−mR=1.5−1∞
Solving, gives v1=−(1.5mR)
Now, again applying the lens formula for the curved surface,