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Question

A quarter horse power motor runs at a speed of 600 rpm. assuming 40% efficiency the work done by the motor in one rotation will be

A
7.46 j
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B
7400 j
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C
74.6 j
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D
746 j
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Solution

The correct option is B 7.46 j
Given,
P=14hp=7464=186.5W
efficiency=40%

ω=2π×60060=20πrad/sec
The power used for doing work with efficiency 40% is,

P=186.5×40100=74.6W

Torque, τ=Pω=74.620π

The work done in one rotation,

W=τ×2π=74.6×2π20π=7.46J

The correct option is A.


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