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Standard XII

Mathematics

Combination

A question pa...

Question

A question paper has two parts P and Q, each containing 10 questions. If a student needs to choose 8 from part P and 4 from part Q, in how many ways can he do that ?

9450

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Solution

The correct option is A 9450
Number of ways to choose 8 questions from part P = $10_{C_{8}}$
Number of ways to choose 4 questions from part Q = $10_{C_{4}}$
Total number of ways
$= 10_{C_{8}} \times 10_{C_{4}}$
$= 10_{C_{2}} \times 10_{C_{4}}$
$= 9450$

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A question paper has two parts P and Q, each containing 10 questions. If a student needs to choose 8 from part P and 4 from part Q, in how many ways can he do that ?

The correct option is A 9450Number of ways to choose 8 questions from part P = 10C8Number of ways to choose 4 questions from part Q = 10C4Total number of ways =10C8×10C4=10C2×10C4=9450

The correct option is A 9450
Number of ways to choose 8 questions from part P = $10_{C_{8}}$
Number of ways to choose 4 questions from part Q = $10_{C_{4}}$
Total number of ways
$= 10_{C_{8}} \times 10_{C_{4}}$
$= 10_{C_{2}} \times 10_{C_{4}}$
$= 9450$