Question

A question paper has two parts-Part A and Part B. Part A contains 5 questions and part B has 4. Each question in part A has an alternative. A student has to attempt at least one question from each part. Find the number of ways in which the student can attempt the question paper.

• A. 3360
  
• B. 1258
  
• C. 3850
  
• D. 3630

Answer 1

The correct option is D 3630

Part A can be attempted in 3 ways
(i) The student do not solve the question.
(ii) The student attempts the first part of the question.
(iii) The student attempts the second (i.e., alternative) part of the question.
$\therefore$ Total number of choices in the first part =$3^5$
Hence, the required number of ways in which a student must attempt at least one question =$3^5-1=242$
Similarily, we can show that there are $2^4-1$
i.e., 15 choices of part B.
Hence the required number of ways =$242\times 15=3630.$