wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A question paper on mathematics consists of twelve questions divided into three parts A, B and C, each containing four questions. In how many ways can an examinee answer five questions, selecting atleast one from each part.

A
624
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
208
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2304
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 624
Total no. of ways
A B C A B C
=(4C1× 4C1× 4C3)×3+(4C14C24C2)×3 ( multiple by 3 as for each A,B,C different combination)
=192+432
=624

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Combinations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon