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Question

A race track is in the form of a ring whose inner circumference is 440 m & outer circumference is 506 m The width of the track is:

A
7 m
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B
21 m
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C
10.5 m
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D
14 m
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Solution

The correct option is C 10.5 m
Let the radius of the outer circle be R and inner circle be r.
Outer circumference =506 m

2×227×R=506 m

R=80.5 m


Inner circumference =440m

2×227×r=440 m

r=70 m
Hence, width of the track =(80.570) m=10.5 m
311834_338717_ans_0a6a4b20aa964dab8cd62fe5727d3ce6.png

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