Question

A race track is in the form of a ring whose outer and inner circumferences are 396 m and 352 m respectively. Find the width of the track.

Answer 1

Given inner circumference$=352$m

Outer circumference$=396$m

the inner radius$=\frac{c}{2\pi }=\frac{352}{2\pi }$m

& outer radius$=\frac{396}{2\pi }$m

So width of track$=$outer$-$inner radii

$=\frac{1}{2\pi }[396-352]$

width$\Rightarrow \frac{1}{2\pi }\times 44=7$m.