We have,
Circumference of circle (1) =220 m
Circumference of circle (2) =286 m
Now,
In circle (1) :-
2πr1=220
πr1=110
r1=110π
r1=110227
r1=110×722
r1=35 m
In circle (2) :-
2πr2=286
πr2=143
r2=143π
r2=143227
r2=143×722
r2=45.5 m
So,
Area of racing track=π(r22−r12)
=227[(45.5)2−(35)2]
=227[2070.25−1225]
=227[845.25]
=22×120.75
=2656.5 m2
Hence, this is the answer.