Question

A radiation is incident on a metal of work function $2.3eV$ . The incident radiation is $600nm$.If the total energy of incident radiation is $23J$, then the number of photoelectrons is

• A. zero
• B. $<{10}^4$
• C. $={10}^4$
• D. $\infty$

Answer 1

Answer: (A)

zero

Wavelength of incident radiation $=600\times {10}^{9}m$
Energy of the photon of radiation in terms of $eV=\frac{hc}{\lambda }$ $=\frac{6.626\times {10}^{-34}\times 3\times {10}^8}{1.6\times {10}^{-19}\times 6\times {10}^{-9}}eV$ $=2.07eV.$
As, we see that work function of metal $>$ energy of incident photon
So, no electrons will be ejected.