A radiation of energy E falls normally on a perfectly reflecting surface. The momentum transfered to the surface is:

E / c

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E / c^{2}

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E c

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2 E / c

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Solution

The correct option is D $2 E / c$

Here momentum transferred is given as $P_{t r a n s f e r r e d} = P_{1} - P_{2}$
$P_{1} = \frac{E}{c}$
$P_{2} = - \frac{E}{c}$
so $P = \frac{E}{c} - (- \frac{E}{c}) = \frac{2 E}{c}$

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