A radiation of energy ‘E’ falls normally on a perfectly reflecting surface. The momentum transferred to the surface is

\frac{E}{c}

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\frac{2 E}{c}

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E c

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\frac{E}{c^{2}}

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Solution

The correct option is B $\frac{2 E}{c}$
$Δ P_{s u r f a c e} = - Δ p = \frac{2 E}{C}$

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A radiation of energy E falls normally on a perfectly reflecting surface. The momentum transferred to the surface

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