A radiation of energy E falls normally on a perfectly reflecting surface. The momentum transferred to the surface

E/C

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2E/C

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E/C²

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Solution

The correct option is B
2E/C

The change in momentum on a perfectly reflecting surface = 2p

where p = momentum of radiation

As P = $\frac{E}{c}$ ∴ Momentum transferred = $\frac{2 E}{c}$

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A radiation of energy ‘E’ falls normally on a perfectly reflecting surface. The momentum transferred to the surface is

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