Question

A radiation of energy=E falls normally on a perfectly reflecting surface.The momentum transferred to the surface is (C=Velocity of light):

• A. E/C²
• B. E/C
• C. 2E/C
• D. 2E/C²

Answer 1

The correct option is C

2E/C

$p=\frac{E}{C}$

For reflecting surface

$\Delta p=p-(-p)=2p=\frac{2E}{c}$