wiz-icon
MyQuestionIcon
MyQuestionIcon
2266
You visited us 2266 times! Enjoying our articles? Unlock Full Access!
Question

A radio can tune over the frequency range of a portion of MW broadcast band: (800 kHz to 1200 kHz). If its LC circuit has an effective inductance of 200 μH, what must be the range of its variable capacitor?

[Hint: For tuning, the natural frequency i.e., the frequency of free oscillations of the LC circuit should be equal to the frequency of the radiowave.]

Open in App
Solution

The range of frequency (ν) of a radio is 800 kHz to 1200 kHz.

Lower tuning frequency, ν1 = 800 kHz = 800 × 103 Hz

Upper tuning frequency, ν2 = 1200 kHz = 1200× 103 Hz

Effective inductance of circuit L = 200 μH = 200 × 10−6 H

Capacitance of variable capacitor for ν1 is given as:

C1

Where,

ω1 = Angular frequency for capacitor C1

Capacitance of variable capacitor for ν2,

C2

Where,

ω2 = Angular frequency for capacitor C2

Hence, the range of the variable capacitor is from 88.04 pF to 198.1 pF.


flag
Suggest Corrections
thumbs-up
15
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Modulation
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon