A radio nuclide with half life T days emits -particles of average kinetic energy E joule - This radionuclide is used as source in a machine which generates electric energy with efficiency - The no-of moles of the nuclide required to generate electrical energy at an initial rate P is Avagadro no- - N A- None of theseB- PTln 2 - D TC- 11-ln 2D- Pl - NE

The correct option is C PT/η NE ln 2 If n = no. of moles Rate of decay = λ n N = nNln^2/T Rate of release of energy = E [ dN/dt ] P = η E [ dN/dt ] = ηnNEln^ ...

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Standard VII

Chemistry

Sub-Atomic Particles

A radio nucli...

Question

A radio nuclide with half life T days emits $β$ -particles of average kinetic energy E joule . This radionuclide is used as source in a machine which generates electric energy with efficiency $η$ . The no.of moles of the nuclide required to generate electrical energy at an initial rate P is ( Avagadro no. =N)

$\frac{P T l n 2}{η N E}$

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$\frac{P T}{η N E}$

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$\frac{P T}{η N E l n 2}$

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None of these

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Solution

The correct option is C
$\frac{P T}{η N E l n 2}$

If n = no. of moles
Rate of decay $= λ n N = \frac{n N l n^{2}}{T}$
Rate of release of energy $= E [\frac{d N}{d t}] P = η E [\frac{d N}{d t}] = η \frac{n N E l n^{2}}{T}$

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The correct option is C PTηNE ln 2 If n = no. of moles Rate of decay =λnN=nNln2T Rate of release of energy =E[dNdt]P=ηE[dNdt]=ηnNEln2T

The correct option is C
$\frac{P T}{η N E l n 2}$

If n = no. of moles
Rate of decay $= λ n N = \frac{n N l n^{2}}{T}$
Rate of release of energy $= E [\frac{d N}{d t}] P = η E [\frac{d N}{d t}] = η \frac{n N E l n^{2}}{T}$