A radio station runs a phone-in contest for listeners. Every 40th caller gets a free smartphone and every 60th caller gets a free laptop. Which caller number is the first to receive both the smartphone and the laptop?
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Solution
The first caller number to win both a smartphone and a laptop has to be a multiple of both 40 and 60 ⇒ LCM (40, 60)
Extracting common factors of 40 and 60:
LCM = 2×2×2×3×5=120
Hence, 120th caller will receive both the smartpone and the laptop.