A radioactive element decays as follows-a P b -2 -c Q d - e R f -1 e 0The relation between a - b - e - - f isA- i f-d-b-8 and ii e-c-a-4B- i f - d - b -8 and ii e - c -1- a -3C- i f - d -2- b -8 and ii e - c -1- a -3D- i f - d -8- b and ii e - c -1- a -4E- i f - d - b -4 and ii e - c -1- a -3

The correct option is B i) f = d = b 8 and ii) e = c +1 = a 3d = b – 7 c = a – 4 f = d = b 8 e = c + 1 = (a – 4) + 1 = a 3 ...

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Standard X

Physics

Alpha Decay

A radioactive...

Question

A radioactive element decays as follows:

_aP^b - 2α → _cQ^d → _eR^f + _-1e⁰

The relation between a, b, e, & f is

i) f = d = b-4 and ii) e = c +1 = a -3

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i) f = d = b-8 and ii) e = c = a -4

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i) f = d = b-8 and ii) e = c +1 = a -3

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i) f = d+2 = b-8 and ii) e = c +1 = a -3

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i) f = d-8 = b and ii) e = c +1 = a -4

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Solution

The correct option is C
i) f = d = b-8 and ii) e = c +1 = a -3

d = b – 7

c = a – 4

f = d = b - 8

e = c + 1 = (a – 4) + 1 = a - 3

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A radioactive element decays as follows: aPb - 2α → cQd → eRf + -1e0 The relation between a, b, e, & f is

The correct option is C i) f = d = b-8 and ii) e = c +1 = a -3d = b – 7 c = a – 4 f = d = b - 8 e = c + 1 = (a – 4) + 1 = a - 3

A radioactive element decays as follows:

_aP^b - 2α → _cQ^d → _eR^f + _-1e⁰

The relation between a, b, e, & f is

The correct option is C
i) f = d = b-8 and ii) e = c +1 = a -3

d = b – 7

c = a – 4

f = d = b - 8

e = c + 1 = (a – 4) + 1 = a - 3